2003年数学建模B题优秀论文(4)

%truck为卡车辆数

truck=(f1*2/28+times*8/60)/8; for i=3:5 for j=1:7

pei((i-3)*7+j)=pin(j)*x((i-1)*7+j); end end for i=1:3 peibi(i)=0;

是

timestot(i)=0; end for i=1:3 for j=1:7

timestot(i)=x((i+1)*7+j)+timestot(i); end end for i=1:3 for j=1:7

peibi(i)=pei((i-1)*7+j)+peibi(i); end

peibi(i)=peibi(i)/timestot(i); end cha=0; for i=1:3

cha=(peibi(i)-29.5)*(peibi(i)-29.5)+cha; end

f=(f1+truck*quan(1)+cha*quan(2)); for j=1:5 sumj(j)=0; end for j=1:5 for i=1:7

是

sumj(j)=sumj(j)+x((j-1)*7+i)*154; end end

%产量约束条件

sumjx=[1.3 1.9 1.2 1.3 1.3]*1e+4; for i=1:5

g(i)=sumjx(i)-sumj(i); end for i=1:7 sumi1(i)=0; sumi2(i)=0; sumi3(i)=0; end for i=1:7 for j=1:2

sumi1(i)=sumi1(i)+x((j-1)*7+i)*154; end end for i=1:7 for j=3:5

sumi2(i)=sumi2(i)+x((j-1)*7+i)*154; end end

是

for i=1:7

sumi3(i)=(sumi1(i)+sumi2(i))/154; end

sumi2x=hl(1,qudian)*1e+4; sumi1x=hl(2,qudian)*1e+4; %岩石矿石的最大运量约束 for i=1:7

g(i+5)=sumi1(i)-sumi1x(i); g(i+12)=sumi2(i)-sumi2x(i); end

%铲车装车时间约束 for i=1:7

g(19+i)=sumi3(i)-96; end

%卸车时间约束 for i=1:5

g(26+i)=sumj(i)/154-160; end

%卡车辆数约束 g(32)=truck-20;

%优化执行程序 %x0为初始值

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