高频电子线路课后习题 - - 张肃文

第2章

3?1解：f0?1MHz2Δf0.7?1?106?990?103?10(kHz)f01?106Q???1002Δf0.710?103取R?10Ω则L?C?QR?01?100?10?159(?H)2?3.14?1061?159(pF)262?6?0L(2?3.14?10)?159?10

113?2解：(1)当?01?或ω?时，产生并联谐振。02L1C1L2C2?(2)当?01?(3)当?01?1或ω02?L1C11或ω02?L1C11时，产生串联谐振。L2C21时，产生并联谐振。L2C2

1L1)R2??jω0LR(1?2)R2?Ljω0CCω0LCC?R3?3证明：Z???112RR?jω0L?R?2R?jω0L(1?2)jω0Cω0LC 223?4解：1?由?15?C??1605??450?C?535得C?40pF(R?jω0L)(R?由?12?C??16052??100?C?5352得C?-1pF?不合理舍去?故采用后一个。2?L?3?

L C C’

11??180?μH?223?12?0?C?C???2?3.14?535?10???450?40??10

3?5解：Q0?11??2126-12?0C0R2?3.14?1.5?10?100?10?5L0?11??112?μH?226-12?0C0?2?3.14?1.5?10?100?10Vom1?10-3Iom???0.2?mA?R5VLom?VCom?Q0VSm?212?1?10-3?212?mV?113?6解：L?2??253?μH??0C2?3.14?1062?100?10?12

??Q0?VC10??100VS0.1C?CX11?2??100?pF??CX?200pFC?CX?0L?2?3.14?106?2?253?10?62?3.14?106?253?10?62?3.14?106?253?10?6RX?????47.7?Ω?QQ02.50.1100?0L?0L11?47.7?j?47.7?j796?Ω?6?12?0CX2?3.14?10?200?10113?7解：L?2??20.2?μH?ω0C?2?3.14?5?106??50?10?12ZX?RX?jf05?106100Q0???2Δf0.7150?10332Δf1002??5.5?5??10620ξ?Q0???6f035?103??2?2?f0.7，则Q??因2Δf0.7，所以应并上21kΩ电阻。 0?0.5Q0，故R?0.5R2πf0CωC3?8证明：4πΔf0.7C??0?g?f02Δf0.7Q

?C?C0?C1?5??20?20?20?18.3?pF?3?9解：C?Ci?2C2?C0?C120?20?20f0?11??41.6?MHz??6?122πLC2?3.140.8?10?18.3?10L?100?C120.8?10?6?20.9?kΩ??20?20??10?1222RP?Q0?C2?C0?C1??20?20?20??R??RiRP?R?1020.9???5?5.88?kΩ???0C20??1??R?5.88?103QL???28.26?6ω0L2?3.14?41.6?10?0.8?102Δf0.7f041.6?106???1.48?MHz?QL28.2

3?12解：1?Zf1?02?Zf1?03?Zf1?R

3?13解：1?L1?L2?C1?C2?ρ1103??159?μH?62?3.14?10?0111??159?pF?226?6?01L1?2?3.14?10??159?10ηR1?20M?1??3.18?μH?6?012?3.14?102?Zf1??01M?2?R2?2?3.14?10?6?3.18?10?6??20?Ω?202L1159?10?6ZP???25?kΩ??12?R1?Rf1?C1?20?20??159?103?Q1??01L1R1?Rf12?3.14?106?159?10?6??2520?204?2Δf0.7??5?C2f0f0106?20?2?2?2??28.2?kHz?Qρ1R110312????02L2?1?2?3.14?950?10?32?159?10?6?177?pF??1?Z22?R2?j??L??021?C???022??1???20?j?2?3.14?106?159?10?6??20?j1006?12?2?3.14?10?177?10??Zf1??01M?2?Z22?2?3.14?10??6?3.18?10?6??0.768?j3.84?Ω?20?j10062

3?15解：?R?L159?10??20????R1RPC50?103?159?10?12?Rf1?0?M?0f0106Q?2?2?1002?f0.714?103

3?16解：1?Rf1??01M?2?R2?10?7?10?6??20???52Rab?2???3?Q??RR1??01L?21?Rf1??10?7?100?10?6??40?k??5?202?01M?01LR1107?10?6??25107?100?10?6??20052?f0.711??2?2??1??22?2?2?1??0.013f0Q200 I1113?17解：????Q??22.522I01.25?2?f??10?103?1??1???Q?300?103???Q?f????0??11R???11.8Q?0C22.5?2?3.14?300?103?2000?10?12?2?f??10?103?1??1???Q300?103???Qf????0??Q?Q??30?22.5?7.51?2ω?串联联谐??L1?375μHL2C?3?18解：???1?L2?125μ?ω?并联联谐?L1?L2?C??I?I012?12?1?Q?302

第3章

4?5解：当f?1MHz时，??β0?β0f1???f?Tβ0?β0f1???f?Tβ0?β0f1???f?T????????????2?50?50?10?1???250?106????5062?49当f?20MHz时，??2?当f?50MHz时，??2??50?20?106?1???250?106????50?50?50?101???250?106?62?12.1????2?5

4?7解：gb?e?gm?Cb?eIE1??0.754?mS?26?β0?1?26??50?1?β0?50?0.754?10?3?37.7?mS?rb?egm37.7?10?3???24?pF?62πfT2?3.14?250?10a?1?rbb?gb?e?1?70?0.754?10?3?1b?ωCb?erbb??2?3.14?107?24?10?12?70?0.1yie?gb?e?j?Cb?e??a?jb??0.754?10?3???a2?b2?0.895?j1.41?mS?j2?3.14?107?24?10?12???1?j0.1?12?0.12j2?3.14?107?3?10?12??1?j0.1?yre??0.0187?j0.187?mS?2222a?b1?0.1gm?a?jb?37.7?10?3??1?j0.1?yfe???37.327?j3.733?mS?a2?b212?0.12?g?j?Cb?c??a?jb??j?C?1?rga?jb?yoe?gce?j?Cb?c?rbb?gmb?c?b?c?bb?ma2?b2a2?b2??1?j0.1???j2?3.14?107?3?10?12?1?70?37.7?10?3?2?0.049?j0.68?mS?2?1?0.1???Av?4?8解：令??A???vo??Av?令??A???vo?mm?g?j?Cb?c??a?jb?????b?c??????4??Q2Δf?4??Q2Δf420.7f0?4????1?2?m得2Δf0.71?m?f0???44?2?1??Q???????20.1f0?4????1?10?10?12?11m2mm得2Δf0.12?m?f0???44?10?1??Q??故Kr0.1?2Δf0.1?2Δf0.742?m??4?10?1????1?m??4?2?1?????4

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