=12
|????|-?AD????AE2????1·AE =1
2×(2)2-1×2×cos45°=0. ∴??????D????1M⊥AE.∴D1M⊥AE.
??????∵?????DM·????AB=(1????????12AE-AD1)·AB =1?????????????????2
AE·AB-AD1·AB =1
2×2×2×cos45°-1×2×cos60°=0,??????∴D????1M⊥AB,∴D1M⊥AB.
又AE∩AB=A,AE、AB?平面ABCE, ∴D1M⊥平面ABCE. ∵D1M?平面D1AE, ∴平面D1AE⊥平面ABCE. 6
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