四边形ABFE 是平行四边形,
∴BE 过点P 。
∴P 为BE 的中点,………………………………………8分 又G 是BC 的中点,
//PG EC ∴,
PG ?平面,AEC EC ?平面AEC
//PG ∴平面AEC …………………………………………12分
19.本题主要考等差数列、数列求和等基础知识:考查推理论证与运算求解能力;考查化归与转化思想,满分12分。
解(I )点1(,)n n a a +在函数2y x =+的图象上,
12n n a a +∴=+
∴数列{}n a 是以首项为2公差为2的等差数列, ··········································· 2分 22(1)2n a n n ∴=+-= ············································································ 4分
(Ⅱ)(22)(1)2
n n S n n +==+ ·································································· 6分 1111(1)1
n S n n n n ==-++, ······································································ 8分 123111111111(1)()()2231
n S S S S n n ∴++++=-+-++-+…… ·························· 10分 1111
n n n =-=++···················································································· 12分 20.本题主要考查概率与统计的基础知识,考查运算求解能力及应用意识。
满分12分。
解:(I )设样本容量为n ,则201222055
n =++++,所以120n = 所以样本的容量为120 ·············································································· 3分 (Ⅱ)设成绩在120分到150分的学生有x 个,
则3020120
x =,所以5x = ·········································································· 3分 (Ⅲ)设成绩在120分到150分的学生中,男生比女生多的事件记为A ,男生数与女生书记为数对(,x y ),则基本事件有:(5,15),(6,14),(7,13),(8,12),(9,
11),
(10,10),(11,9),(12,8),(13,7),(14,6),(15,5),(16,4),(17,
3),
(18,2),(19,1),(20,0),共16对 ··············································· 9分
第6页 共8页 而事件A 包含的事件有:(11,9),(12,8),(13,7),(14,6),(15,5),(16,
4),
(17,3),(18,2),(19,1),(20,0)共10对。 所以105()168P A == ················································································· 12分 21.本题主要考查利用导数研究函数的性质,考查运算求解能力及数形结合思想。满分12分。
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