简单的一元多项式计算器程序(4)

s->expn=pa->expn; s->next=NULL;

pc->next=s;

pc=s;

pa=pa->next; } else {

x=pa->coef+pb->coef;

if(x!=0) { s=(POLY)malloc(sizeof(struct PNode)); s->coef=x; s->expn=pa->expn; s->next=NULL;

pc->next=s;

pc=s;

}

pa=pa->next;

pb=pb->next;

} } while(pa) { s=(POLY)malloc(sizeof(struct PNode)); s->coef=pa->coef; s->expn=pa->expn; s->next=NULL;

pc->next=s;

pc=s;

pa=pa->next; } while(pb) { s=(POLY)malloc(sizeof(struct PNode)); s->coef=pb->coef;

s->expn=pb->expn;

s->next=NULL;

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pc->next=s; pc=s;

pb=pb->next; } }

void SubtractPoly(POLY Ha, POLY Hb, POLY &Hc) //一元多项式的相减操作，即实现Hc=Ha-Hb

{

int x;

POLY pa,pb,pc,s;

Hc=(POLY)malloc(sizeof(struct PNode)); Hc->next=NULL; pc=Hc; pa=Ha->next;

pb=Hb->next; while(pa&&pb) { if(pa->expnexpn) {

s=(POLY)malloc(sizeof(struct PNode)); s->coef=pb->coef; s->expn=pb->expn; s->next=NULL;

pc->next=s;

pc=s;

pb=pb->next; }

else if(pa->expn>pb->expn) { s=(POLY)malloc(sizeof(struct PNode)); s->coef=pa->coef; s->expn=pa->expn; s->next=NULL;

pc->next=s;

pc=s;

pa=pa->next; } else

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{

x=pa->coef-pb->coef;

if(x!=0)

{ s=(POLY)malloc(sizeof(struct PNode)); s->coef=x; s->expn=pa->expn; s->next=NULL;

pc->next=s;

pc=s;

}

pa=pa->next;

pb=pb->next;

} } while(pa) { s=(POLY)malloc(sizeof(struct PNode)); s->coef=pa->coef; s->expn=pa->expn; s->next=NULL;

pc->next=s;

pc=s;

pa=pa->next; } while(pb) { s=(POLY)malloc(sizeof(struct PNode)); s->coef=-pb->coef; s->expn=pb->expn; s->next=NULL;

pc->next=s;

pc=s;

pb=pb->next; } }

void main() {

POLY Ha,Hb,Hc;

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int n;

printf(\ 创建第一个多项式中…\\n\\n\ printf(\请输入第一个多项式项数:\ scanf(\ CreatPoly(Ha,n);

printf(\第一个多项式为：\\n\ OutputPoly(Ha);

printf(\ 创建第二个多项式中…\\n\\n\

printf(\请输入第二个多项式项数:\ scanf(\ CreatPoly(Hb,n);

printf(\第二个多项式为：\\n\ OutputPoly(Hb); SubtractPoly(Ha,Hb,Hc); printf(\多项式差：\\n\ SubtractPoly(Ha,Hb,Hc); OutputPoly(Hc);

printf(\多项式和：\\n\ SubtractPoly2(Ha,Hb,Hc);

OutputPoly(Hc);

}

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完成日期：2010年7月19日

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